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(3G)=(3G)-2(3G)^2
We move all terms to the left:
(3G)-((3G)-2(3G)^2)=0
determiningTheFunctionDomain -(3G-23G^2)+3G=0
We get rid of parentheses
23G^2-3G+3G=0
We add all the numbers together, and all the variables
23G^2=0
a = 23; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·23·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$G=\frac{-b}{2a}=\frac{0}{46}=0$
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